Radiation

Thermal radiation is heat carried by electromagnetic waves — it needs no medium. Learn the Stefan–Boltzmann law, emissivity, black and grey bodies, Wien's law, view factors, and radiation shields.

Sunlight warms your face across 150 million km of vacuum. A campfire warms you even when the air is cold. That's thermal radiation — every object above absolute zero emits it, and hot objects emit enormously more (∝ T⁴).

Radiation dominates at high temperatures (furnaces, re-entry vehicles, combustion) and in vacuum (spacecraft), and matters even at room temperature for buildings and electronics.

An analogy

A glowing electric heater: you feel warm on the side facing it but not behind a sheet of foil — radiation travels in straight lines and can be blocked or reflected.

Everything radiates

Emission grows with the fourth power of absolute temperature: doubling T (in K) multiplies emission by 16. At room temperature the radiation is infrared; at ~800 K objects start glowing red.

Emissivity and surface finish

A black body (ε = 1) is the ideal emitter/absorber. Real surfaces: polished aluminium ≈ 0.05, oxidised steel ≈ 0.8, paint ≈ 0.9, human skin ≈ 0.98. Kirchhoff's law: at the same wavelength, emissivity = absorptivity. Low-ε coatings (low-e glass, foil) cut radiative loss.

Spectral selectivity

The Sun (≈ 5800 K) peaks at 0.5 µm (visible); room-temperature objects peak near 10 µm. Solar collectors use surfaces that absorb visible but emit little infrared; white roofs reflect sunlight but emit infrared well — staying cool.

View factors and enclosures

Exchange between surfaces depends on how much each 'sees' of the other (view factor) and on their emissivities — solved with radiosity networks. Radiation shields (multi-layer insulation on spacecraft) add resistances in series. Participating gases (CO₂, H₂O) absorb and emit in furnaces and the atmosphere.

Formulas

Worked example: Radiation from a hot plate

Given: A = 1 m², ε = 0.9; T_s = 500 K, surroundings 300 K

Find: Net radiative loss.

Answer: ≈ 2.8 kW

Worked example: Wien's law

Given: Sun ≈ 5800 K, human ≈ 310 K

Find: Peak wavelengths.

Answer: 0.5 µm and 9.3 µm — why thermal cameras work in 8–14 µm

Common mistakes

Applications

Key takeaways

Going further