Humidification

Humidification operations transfer water between air and water. Learn humidity, relative humidity, dew point, wet-bulb temperature, psychrometric charts, humid heat and enthalpy, cooling towers (range, approach, evaporation, make-up, blowdown) and air conditioning processes.

Cooling towers reject heat from power plants and refineries by evaporating a small fraction of the water; air conditioning adds or removes moisture; dryers depend on air's capacity to hold water. All rely on psychrometry — the thermodynamics of moist air.

Evaporating 1 kg of water removes about 2.4 MJ — which is why cooling towers are so effective.

An analogy

Sweating on a breezy day: evaporation cools your skin. A cooling tower is a giant sweating machine for plant water.

Moist air basics

Air holds more water when warm. Relative humidity compares the actual vapour pressure with saturation; dew point is where cooling makes water condense; wet-bulb temperature is what an evaporating wet surface reaches.

Psychrometric chart

The chart plots humidity vs dry-bulb temperature with lines of RH, wet-bulb, enthalpy and specific volume. Processes — heating, cooling, humidifying, dehumidifying, mixing — are lines on the chart.

Cooling towers

Hot water is sprayed over fill while air flows through; water cools toward the wet-bulb temperature. Range = inlet − outlet water temperature; approach = outlet − wet bulb (typically 3–6 K). Evaporation losses must be replaced (make-up), and blowdown controls dissolved-solid build-up (cycles of concentration).

Design and water treatment

Merkel's equation integrates enthalpy driving force for tower sizing (KaV/L). Drift eliminators, fan control, and water treatment (scale, corrosion, biofouling, Legionella) are key. Hybrid and dry coolers save water in arid regions.

Formulas

Worked example: Humidity of air

Given: 30 °C, 60 % RH, 101.3 kPa; p_sat(30 °C) = 4.246 kPa

Find: Absolute humidity.

Answer: ≈ 16 g water/kg dry air

Worked example: Cooling tower evaporation

Given: 1000 m³/h water cooled 40 → 30 °C

Find: Heat rejected and evaporation.

Answer: 11.6 MW, ≈ 17 t/h evaporated

Common mistakes

Applications

Key takeaways

Going further