Humidification
Humidification operations transfer water between air and water. Learn humidity, relative humidity, dew point, wet-bulb temperature, psychrometric charts, humid heat and enthalpy, cooling towers (range, approach, evaporation, make-up, blowdown) and air conditioning processes.
Cooling towers reject heat from power plants and refineries by evaporating a small fraction of the water; air conditioning adds or removes moisture; dryers depend on air's capacity to hold water. All rely on psychrometry — the thermodynamics of moist air.
Evaporating 1 kg of water removes about 2.4 MJ — which is why cooling towers are so effective.
An analogy
Sweating on a breezy day: evaporation cools your skin. A cooling tower is a giant sweating machine for plant water.
Moist air basics
Air holds more water when warm. Relative humidity compares the actual vapour pressure with saturation; dew point is where cooling makes water condense; wet-bulb temperature is what an evaporating wet surface reaches.
Psychrometric chart
The chart plots humidity vs dry-bulb temperature with lines of RH, wet-bulb, enthalpy and specific volume. Processes — heating, cooling, humidifying, dehumidifying, mixing — are lines on the chart.
Cooling towers
Hot water is sprayed over fill while air flows through; water cools toward the wet-bulb temperature. Range = inlet − outlet water temperature; approach = outlet − wet bulb (typically 3–6 K). Evaporation losses must be replaced (make-up), and blowdown controls dissolved-solid build-up (cycles of concentration).
Design and water treatment
Merkel's equation integrates enthalpy driving force for tower sizing (KaV/L). Drift eliminators, fan control, and water treatment (scale, corrosion, biofouling, Legionella) are key. Hybrid and dry coolers save water in arid regions.
Formulas
- Humidity:
H = 0.622 p_v / (P − p_v) - Relative humidity:
RH = p_v / p_sat(T) - Moist-air enthalpy:
h ≈ 1.006 T + H (2501 + 1.86 T) kJ/kg dry air - Cooling tower evaporation:
ṁ_evap ≈ Q / λ (≈ 0.15–0.2 % of flow per K range) - Blowdown:
B = E/(CoC − 1)
Worked example: Humidity of air
Given: 30 °C, 60 % RH, 101.3 kPa; p_sat(30 °C) = 4.246 kPa
Find: Absolute humidity.
- p_v = 0.6 × 4.246 = 2.548 kPa
- H = 0.622 × 2.548/(101.325 − 2.548) = 0.0160 kg/kg
Answer: ≈ 16 g water/kg dry air
Worked example: Cooling tower evaporation
Given: 1000 m³/h water cooled 40 → 30 °C
Find: Heat rejected and evaporation.
- Q = 277.8 kg/s × 4.18 × 10 = 11.6 MW
- Evaporation = 11.6 × 10⁶/2.43 × 10⁶ = 4.8 kg/s = 17.2 t/h (1.7 %)
Answer: 11.6 MW, ≈ 17 t/h evaporated
Common mistakes
- Wrong: Expecting a tower to cool below the wet bulb. — Right: Wet-bulb is the theoretical limit; approach is typically 3–6 K.
- Wrong: Ignoring blowdown. — Right: Without blowdown, dissolved solids build up and scale.
Applications
- Power & refineries: Cooling towers reject condenser and process heat.
- HVAC: Humidifiers, dehumidifiers and evaporative coolers.
- Industrial drying & paper: Air humidity control in dryers and paper machines.
Key takeaways
- H = 0.622 p_v/(P − p_v); RH = p_v/p_sat.
- Wet bulb is the cooling limit.
- Evaporation ≈ Q/λ; blowdown = E/(CoC − 1).
- Psychrometric charts map air processes.
Going further
- Merkel number: KaV/L integrated from enthalpy driving force sizes tower fill.
- Legionella control: Biocides, monitoring and design to prevent outbreaks.
- Hybrid coolers: Combine dry and wet operation to save water.